杭电ACMhdu1163
杭电ACMhdu1163
杭电hdu acm资料所用杭电的acm题
Problem DescriptionConsider the aggregate An= { 1, 2, …, n }. For example, A1={1}, A3={1,2,3}. A subset sequence is defined as a array of a non-empty subset. Sort all the subset sequece of An in ...
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杭电acm解题报告 详细解析2000-2099 适合acm初学者
二分匹配及其应用 搜索入门 母函数 组合博弈入门 特殊的数
Arbitrage Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5272 Accepted Submission(s): 2418 Problem Description ...Arbitrage is the u
Java代码import java.util.*;public class Main {public static void main(String[] args) {String color;Scanner scanner = new Scanner(System.in);HashMapcolorsMap = new HashMap<>();...
Problem DescriptionNowadays, we all know that Computer College is the biggest department in HDU. But, maybe you don’t know that Computer College had ever been split into Computer College and Software...
#include #include using namespace std; __int64 a,b,c; int isluck(){ int i,j; __int64 t; for(i=0;i;i++){ if(a+b==c)return 1; if(a*b==c)return 1; if(a!=0&&b!=0&&(a%b==c || b%a==c))return 1;
杭电OJ训练指南
Train Problem I Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25008 Accepted Submission(s): 9435 Problem Description ...
#include #include int a[10000],b[10000],s[10000]; int la,lb,lc,l; char str[10000]; void read(int a[],int *la){ scanf("%s",str); *la=strlen(str)-1; l=0; for(int i=*la;i>=0;i--){
#include char str[1001]; int main(){ while(scanf("%s",str)&&(str[0]-'0')){ int i=0; int sum=0; while(str[i]){ sum+=str[i++]-'0'; } int n=sum;
亲和串 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5641 Accepted Submission(s): 2546 ...人随着岁数的增长是越大越聪明还是越大越笨，这是一
杭电ACM hdu 2079 选课时间的解题报告。
Least Common Multiple Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20576 Accepted Submission(s): 7674 Problem Description ...The l
畅通工程 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 12078 Accepted Submission(s): 4924 Problem Description ...省政府“畅通工程”的目标...
A simple problem Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2583 Accepted Submission(s): 890 ...Zty很痴迷数学问题....
题目来自杭电ACM: acm.hdu.edu.cn Max Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 188070 Accepted Submission(s): 43819 Problem D
Eddy's picture Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 7800 Accepted Submission(s): 3956 Problem Description Eddy begins to
小Q系列故事——最佳裁判 Time Limit: 500/200 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 1238 Accepted Submission(s): 600 ... 过去的2012年对小Ｑ来说是很悲
最短路径问题 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7754 Accepted Submission(s): 2314 ...给你n个点，m条无向边，每条边都有长度d和
To The Max Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6909 Accepted Submission(s): 3328 Problem Description ...Given a two-dimen
The 3n + 1 problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15209 Accepted Submission(s): 5602 Problem Description ...
Biker's Trip Odometer Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2810 Accepted Submission(s): 1922 Problem Description ...Most b
杭电ACM课件，与感兴趣的同学分享，内容比较简单，适合初学者。
N！Again Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 2395 Accepted Submission(s): 1338 Problem Description ...WhereIsHeroFrom:
#include int main(){ int step,mod; int m[100001]; while(~scanf("%d%d",&step,&mod)){ m[0]=0; int i; for(i=0;i;i++){ m[i+1]=(m[i]+step)%mod;
Problem DescriptionYour task is to Calculate the sum of some integers.InputInput contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line....